(x^2-4)(2x+5)=0

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Solution for (x^2-4)(2x+5)=0 equation:


Simplifying
(x2 + -4)(2x + 5) = 0

Reorder the terms:
(-4 + x2)(2x + 5) = 0

Reorder the terms:
(-4 + x2)(5 + 2x) = 0

Multiply (-4 + x2) * (5 + 2x)
(-4(5 + 2x) + x2(5 + 2x)) = 0
((5 * -4 + 2x * -4) + x2(5 + 2x)) = 0
((-20 + -8x) + x2(5 + 2x)) = 0
(-20 + -8x + (5 * x2 + 2x * x2)) = 0
(-20 + -8x + (5x2 + 2x3)) = 0
(-20 + -8x + 5x2 + 2x3) = 0

Solving
-20 + -8x + 5x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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